5k^2+9k+1=0

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Solution for 5k^2+9k+1=0 equation:



5k^2+9k+1=0
a = 5; b = 9; c = +1;
Δ = b2-4ac
Δ = 92-4·5·1
Δ = 61
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{61}}{2*5}=\frac{-9-\sqrt{61}}{10} $
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{61}}{2*5}=\frac{-9+\sqrt{61}}{10} $

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